An electron (e^-) is moving in the North dire | vedclass

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(B) The force on a moving charge in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.For an electron,the

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West

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(B) The force on a moving charge in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.For an electron,the charge $q = -e$.The velocity $\vec{v}$ is in the North direction (let this be $+\hat{j}$).The magnetic field $\vec{B}$ is in the upward direction (let this be $+\hat{k}$).Calculating the cross product: $\vec{v} 	imes \vec{B} = (v\hat{j}) 	imes (B\hat{k}) = vB(\hat{j} 	imes \hat{k}) = vB\hat{i}$ (East direction).Now,applying the charge: $\vec{F} = -e(vB\hat{i}) = -evB\hat{i}$.The negative sign indicates the force is in the opposite direction of East,which is West.Therefore,the electron will deviate towards the West.

An electron $(e^-)$ is moving in the North direction and the magnetic field at this place is in the upward direction. Then,the electron $(e^-)$ will be deviated towards:

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